ASVAB Math Knowledge Practice Test 197081

Question 3 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 3b - 3b = 2b - 2z - 6 for b in terms of z.

-2\(\frac{1}{2}\)z - \(\frac{1}{4}\)
z - 6
4z - 8
1\(\frac{2}{7}\)z + \(\frac{1}{7}\)