When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 4c + 3c = 9c - 2z - 2 for c in terms of z.
| -\(\frac{2}{15}\)z + \(\frac{1}{3}\) | |
| -6z - 3 | |
| -\(\frac{1}{2}\)z + \(\frac{3}{4}\) | |
| z + \(\frac{2}{5}\) |