| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.90 |
| Score | 0% | 58% |
A trapezoid is a quadrilateral with one set of __________ sides.
equal angle |
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parallel |
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right angle |
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equal length |
A trapezoid is a quadrilateral with one set of parallel sides.
The dimensions of this cube are height (h) = 1, length (l) = 4, and width (w) = 1. What is the surface area?
| 18 | |
| 68 | |
| 202 | |
| 232 |
The surface area of a cube is (2 x length x width) + (2 x width x height) + (2 x length x height):
sa = 2lw + 2wh + 2lh
sa = (2 x 4 x 1) + (2 x 1 x 1) + (2 x 4 x 1)
sa = (8) + (2) + (8)
sa = 18
Solve for b:
b2 + 12b + 17 = 3b - 1
| 6 or 1 | |
| 9 or 4 | |
| -3 or -6 | |
| 9 or 8 |
The first step to solve a quadratic expression that's not set to zero is to solve the equation so that it is set to zero:
b2 + 12b + 17 = 3b - 1
b2 + 12b + 17 + 1 = 3b
b2 + 12b - 3b + 18 = 0
b2 + 9b + 18 = 0
Next, factor the quadratic equation:
b2 + 9b + 18 = 0
(b + 3)(b + 6) = 0
For this expression to be true, the left side of the expression must equal zero. Therefore, either (b + 3) or (b + 6) must equal zero:
If (b + 3) = 0, b must equal -3
If (b + 6) = 0, b must equal -6
So the solution is that b = -3 or -6
Which types of triangles will always have at least two sides of equal length?
equilateral, isosceles and right |
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isosceles and right |
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equilateral and isosceles |
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equilateral and right |
An isosceles triangle has two sides of equal length. An equilateral triangle has three sides of equal length. In a right triangle, two sides meet at a right angle.
If the area of this square is 49, what is the length of one of the diagonals?
| 9\( \sqrt{2} \) | |
| 7\( \sqrt{2} \) | |
| 8\( \sqrt{2} \) | |
| 2\( \sqrt{2} \) |
To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:
a = s2
so the length of one side of the square is:
s = \( \sqrt{a} \) = \( \sqrt{49} \) = 7
The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:
c2 = a2 + b2
c2 = 72 + 72
c2 = 98
c = \( \sqrt{98} \) = \( \sqrt{49 x 2} \) = \( \sqrt{49} \) \( \sqrt{2} \)
c = 7\( \sqrt{2} \)