ASVAB Math Knowledge Practice Test 197976 Results

Your Results Global Average
Questions 5 5
Correct 0 2.90
Score 0% 58%

Review

1

A trapezoid is a quadrilateral with one set of __________ sides.

70% Answer Correctly

equal angle

parallel

right angle

equal length


Solution

A trapezoid is a quadrilateral with one set of parallel sides.


2

The dimensions of this cube are height (h) = 1, length (l) = 4, and width (w) = 1. What is the surface area?

51% Answer Correctly
18
68
202
232

Solution

The surface area of a cube is (2 x length x width) + (2 x width x height) + (2 x length x height):

sa = 2lw + 2wh + 2lh
sa = (2 x 4 x 1) + (2 x 1 x 1) + (2 x 4 x 1)
sa = (8) + (2) + (8)
sa = 18


3

Solve for b:
b2 + 12b + 17 = 3b - 1

48% Answer Correctly
6 or 1
9 or 4
-3 or -6
9 or 8

Solution

The first step to solve a quadratic expression that's not set to zero is to solve the equation so that it is set to zero:

b2 + 12b + 17 = 3b - 1
b2 + 12b + 17 + 1 = 3b
b2 + 12b - 3b + 18 = 0
b2 + 9b + 18 = 0

Next, factor the quadratic equation:

b2 + 9b + 18 = 0
(b + 3)(b + 6) = 0

For this expression to be true, the left side of the expression must equal zero. Therefore, either (b + 3) or (b + 6) must equal zero:

If (b + 3) = 0, b must equal -3
If (b + 6) = 0, b must equal -6

So the solution is that b = -3 or -6


4

Which types of triangles will always have at least two sides of equal length?

53% Answer Correctly

equilateral, isosceles and right

isosceles and right

equilateral and isosceles

equilateral and right


Solution

An isosceles triangle has two sides of equal length. An equilateral triangle has three sides of equal length. In a right triangle, two sides meet at a right angle.


5

If the area of this square is 49, what is the length of one of the diagonals?

68% Answer Correctly
9\( \sqrt{2} \)
7\( \sqrt{2} \)
8\( \sqrt{2} \)
2\( \sqrt{2} \)

Solution

To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:

a = s2

so the length of one side of the square is:

s = \( \sqrt{a} \) = \( \sqrt{49} \) = 7

The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:

c2 = a2 + b2
c2 = 72 + 72
c2 = 98
c = \( \sqrt{98} \) = \( \sqrt{49 x 2} \) = \( \sqrt{49} \) \( \sqrt{2} \)
c = 7\( \sqrt{2} \)