ASVAB Math Knowledge Practice Test 198434 Results

Your Results Global Average
Questions 5 5
Correct 0 3.41
Score 0% 68%

Review

1

What is the circumference of a circle with a radius of 16?

70% Answer Correctly
2π
32π
3π
7π

Solution

The formula for circumference is circle diameter x π. Circle diameter is 2 x radius:

c = πd
c = π(2 * r)
c = π(2 * 16)
c = 32π


2

To multiply binomials, use the FOIL method. Which of the following is not a part of the FOIL method?

83% Answer Correctly

Last

Inside

First

Odd


Solution

To multiply binomials, use the FOIL method. FOIL stands for First, Outside, Inside, Last and refers to the position of each term in the parentheses.


3

A(n) __________ is two expressions separated by an equal sign.

76% Answer Correctly

equation

formula

problem

expression


Solution

An equation is two expressions separated by an equal sign. The key to solving equations is to repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.


4

If the area of this square is 16, what is the length of one of the diagonals?

68% Answer Correctly
4\( \sqrt{2} \)
8\( \sqrt{2} \)
2\( \sqrt{2} \)
7\( \sqrt{2} \)

Solution

To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:

a = s2

so the length of one side of the square is:

s = \( \sqrt{a} \) = \( \sqrt{16} \) = 4

The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:

c2 = a2 + b2
c2 = 42 + 42
c2 = 32
c = \( \sqrt{32} \) = \( \sqrt{16 x 2} \) = \( \sqrt{16} \) \( \sqrt{2} \)
c = 4\( \sqrt{2} \)


5

The endpoints of this line segment are at (-2, 10) and (2, -2). What is the slope-intercept equation for this line?

41% Answer Correctly
y = x - 3
y = -3x + 4
y = -2x - 4
y = -1\(\frac{1}{2}\)x - 4

Solution

The slope-intercept equation for a line is y = mx + b where m is the slope and b is the y-intercept of the line. From the graph, you can see that the y-intercept (the y-value from the point where the line crosses the y-axis) is 4. The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, 10) and (2, -2) so the slope becomes:

m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(-2.0) - (10.0)}{(2) - (-2)} \) = \( \frac{-12}{4} \)
m = -3

Plugging these values into the slope-intercept equation:

y = -3x + 4