ASVAB Math Knowledge Practice Test 199036 Results

Your Results Global Average
Questions 5 5
Correct 0 3.56
Score 0% 71%

Review

1

The formula for the area of a circle is which of the following?

76% Answer Correctly

a = π d

a = π d2

a = π r

a = π r2


Solution

The circumference of a circle is the distance around its perimeter and equals π (approx. 3.14159) x diameter: c = π d. The area of a circle is π x (radius)2 : a = π r2.


2

The dimensions of this cylinder are height (h) = 3 and radius (r) = 4. What is the volume?

62% Answer Correctly
3π
324π
48π
320π

Solution

The volume of a cylinder is πr2h:

v = πr2h
v = π(42 x 3)
v = 48π


3

What is 3a - 5a?

79% Answer Correctly
-2a
-2
-2a2
a2

Solution

To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.

3a - 5a = -2a


4

On this circle, line segment AB is the:

70% Answer Correctly

chord

circumference

diameter

radius


Solution

A circle is a figure in which each point around its perimeter is an equal distance from the center. The radius of a circle is the distance between the center and any point along its perimeter. A chord is a line segment that connects any two points along its perimeter. The diameter of a circle is the length of a chord that passes through the center of the circle and equals twice the circle's radius (2r).


5

If the area of this square is 25, what is the length of one of the diagonals?

68% Answer Correctly
3\( \sqrt{2} \)
6\( \sqrt{2} \)
5\( \sqrt{2} \)
7\( \sqrt{2} \)

Solution

To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:

a = s2

so the length of one side of the square is:

s = \( \sqrt{a} \) = \( \sqrt{25} \) = 5

The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:

c2 = a2 + b2
c2 = 52 + 52
c2 = 50
c = \( \sqrt{50} \) = \( \sqrt{25 x 2} \) = \( \sqrt{25} \) \( \sqrt{2} \)
c = 5\( \sqrt{2} \)