ASVAB Math Knowledge Practice Test 199266 Results

Your Results Global Average
Questions 5 5
Correct 0 3.96
Score 0% 79%

Review

1

If the area of this square is 64, what is the length of one of the diagonals?

68% Answer Correctly
8\( \sqrt{2} \)
3\( \sqrt{2} \)
6\( \sqrt{2} \)
9\( \sqrt{2} \)

Solution

To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:

a = s2

so the length of one side of the square is:

s = \( \sqrt{a} \) = \( \sqrt{64} \) = 8

The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:

c2 = a2 + b2
c2 = 82 + 82
c2 = 128
c = \( \sqrt{128} \) = \( \sqrt{64 x 2} \) = \( \sqrt{64} \) \( \sqrt{2} \)
c = 8\( \sqrt{2} \)


2

A right angle measures:

91% Answer Correctly

360°

90°

45°

180°


Solution

A right angle measures 90 degrees and is the intersection of two perpendicular lines. In diagrams, a right angle is indicated by a small box completing a square with the perpendicular lines.


3

A coordinate grid is composed of which of the following?

91% Answer Correctly

origin

y-axis

x-axis

all of these


Solution

The coordinate grid is composed of a horizontal x-axis and a vertical y-axis. The center of the grid, where the x-axis and y-axis meet, is called the origin.


4

Simplify 6a x 3b.

86% Answer Correctly
18\( \frac{a}{b} \)
18\( \frac{b}{a} \)
18ab
18a2b2

Solution

To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.

6a x 3b = (6 x 3) (a x b) = 18ab


5

Solve for a:
-3a + 5 = 4 + a

59% Answer Correctly
2
\(\frac{1}{4}\)
1\(\frac{1}{5}\)
-1

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.

-3a + 5 = 4 + a
-3a = 4 + a - 5
-3a - a = 4 - 5
-4a = -1
a = \( \frac{-1}{-4} \)
a = \(\frac{1}{4}\)