ASVAB Math Knowledge Practice Test 199342

Question 2 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve -6c + 7c = 8c + 7x - 3 for c in terms of x.

\(\frac{2}{5}\)x + \(\frac{1}{2}\)
x + \(\frac{3}{14}\)
-\(\frac{1}{2}\)x - \(\frac{1}{2}\)
-\(\frac{1}{2}\)x - \(\frac{1}{3}\)