ASVAB Math Knowledge Practice Test 19971

Question 2 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve -4c + 9c = 4c + 5z + 9 for c in terms of z.

\(\frac{2}{5}\)z - \(\frac{1}{2}\)
z + 4
-1\(\frac{7}{8}\)z + \(\frac{1}{4}\)
\(\frac{1}{2}\)z - 1\(\frac{1}{8}\)