ASVAB Math Knowledge Practice Test 200286

Question 2 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve -5a + 4a = -4a + z + 5 for a in terms of z.

3z - 5
1\(\frac{1}{7}\)z + \(\frac{2}{7}\)
-\(\frac{1}{2}\)z + \(\frac{1}{2}\)
1\(\frac{1}{8}\)z + \(\frac{1}{4}\)