ASVAB Math Knowledge Practice Test 200345

Question 3 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve -9b + 7b = 9b - 3z - 8 for b in terms of z.

\(\frac{5}{9}\)z + \(\frac{4}{9}\)
-\(\frac{1}{3}\)z - \(\frac{2}{3}\)
1\(\frac{5}{8}\)z + \(\frac{7}{8}\)
7z - 3\(\frac{1}{2}\)