| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.47 |
| Score | 0% | 69% |
Simplify (7a)(9ab) + (5a2)(6b).
| 33ab2 | |
| 93a2b | |
| -33ab2 | |
| 33a2b |
To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.
(7a)(9ab) + (5a2)(6b)
(7 x 9)(a x a x b) + (5 x 6)(a2 x b)
(63)(a1+1 x b) + (30)(a2b)
63a2b + 30a2b
93a2b
What is 4a + 8a?
| 12a | |
| 12a2 | |
| 12 | |
| 32a |
To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.
4a + 8a = 12a
If AD = 12 and BD = 2, AB = ?
| 10 | |
| 12 | |
| 14 | |
| 9 |
The entire length of this line is represented by AD which is AB + BD:
AD = AB + BD
Solving for AB:AB = AD - BD
The endpoints of this line segment are at (-2, 6) and (2, -4). What is the slope-intercept equation for this line?
| y = 1\(\frac{1}{2}\)x + 0 | |
| y = -3x + 3 | |
| y = 2x - 3 | |
| y = -2\(\frac{1}{2}\)x + 1 |
The slope-intercept equation for a line is y = mx + b where m is the slope and b is the y-intercept of the line. From the graph, you can see that the y-intercept (the y-value from the point where the line crosses the y-axis) is 1. The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, 6) and (2, -4) so the slope becomes:
m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(-4.0) - (6.0)}{(2) - (-2)} \) = \( \frac{-10}{4} \)Plugging these values into the slope-intercept equation:
y = -2\(\frac{1}{2}\)x + 1
Which of the following expressions contains exactly two terms?
quadratic |
|
binomial |
|
monomial |
|
polynomial |
A monomial contains one term, a binomial contains two terms, and a polynomial contains more than two terms.