ASVAB Math Knowledge Practice Test 201298

Question 5 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 9c + 4c = 2c - 3z - 6 for c in terms of z.

9z - 2
1\(\frac{1}{8}\)z - \(\frac{3}{4}\)
-\(\frac{2}{5}\)z - \(\frac{2}{5}\)
-z - \(\frac{6}{7}\)