ASVAB Math Knowledge Practice Test 201435

Question 4 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve -3c - 5c = -9c + 3z + 5 for c in terms of z.

1\(\frac{1}{3}\)z + \(\frac{5}{6}\)
1\(\frac{2}{7}\)z + \(\frac{2}{7}\)
-z + \(\frac{7}{12}\)
\(\frac{3}{11}\)z + \(\frac{3}{11}\)