ASVAB Math Knowledge Practice Test 202352 Results

Your Results Global Average
Questions 5 5
Correct 0 3.22
Score 0% 64%

Review

1

Simplify (2a)(6ab) + (8a2)(2b).

65% Answer Correctly
28ab2
80a2b
4ab2
28a2b

Solution

To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.

(2a)(6ab) + (8a2)(2b)
(2 x 6)(a x a x b) + (8 x 2)(a2 x b)
(12)(a1+1 x b) + (16)(a2b)
12a2b + 16a2b
28a2b


2

If the area of this square is 9, what is the length of one of the diagonals?

68% Answer Correctly
4\( \sqrt{2} \)
7\( \sqrt{2} \)
3\( \sqrt{2} \)
\( \sqrt{2} \)

Solution

To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:

a = s2

so the length of one side of the square is:

s = \( \sqrt{a} \) = \( \sqrt{9} \) = 3

The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:

c2 = a2 + b2
c2 = 32 + 32
c2 = 18
c = \( \sqrt{18} \) = \( \sqrt{9 x 2} \) = \( \sqrt{9} \) \( \sqrt{2} \)
c = 3\( \sqrt{2} \)


3

If angle a = 28° and angle b = 36° what is the length of angle c?

71% Answer Correctly
108°
116°
122°
101°

Solution

The sum of the interior angles of a triangle is 180°:
180° = a° + b° + c°
c° = 180° - a° - b°
c° = 180° - 28° - 36° = 116°


4

Which of the following is not true about both rectangles and squares?

63% Answer Correctly

the lengths of all sides are equal

the perimeter is the sum of the lengths of all four sides

all interior angles are right angles

the area is length x width


Solution

A rectangle is a parallelogram containing four right angles. Opposite sides (a = c, b = d) are equal and the perimeter is the sum of the lengths of all sides (a + b + c + d) or, comonly, 2 x length x width. The area of a rectangle is length x width. A square is a rectangle with four equal length sides. The perimeter of a square is 4 x length of one side (4s) and the area is the length of one side squared (s2).


5

Solve for y:
-7y + 7 < -4 - 2y

55% Answer Correctly
y < 2\(\frac{1}{5}\)
y < -4
y < 1\(\frac{4}{5}\)
y < -\(\frac{7}{8}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the < sign and the answer on the other.

-7y + 7 < -4 - 2y
-7y < -4 - 2y - 7
-7y + 2y < -4 - 7
-5y < -11
y < \( \frac{-11}{-5} \)
y < 2\(\frac{1}{5}\)