When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 3a - 3a = 5a + 6y - 2 for a in terms of y.
| 4y + 1 | |
| 1\(\frac{2}{13}\)y - \(\frac{4}{13}\) | |
| -4\(\frac{1}{2}\)y + 1 | |
| -\(\frac{5}{16}\)y - \(\frac{3}{16}\) |