When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 4a + a = 8a + 7y + 1 for a in terms of y.
| -1\(\frac{1}{2}\)y - \(\frac{1}{4}\) | |
| -4\(\frac{1}{3}\)y + 2\(\frac{2}{3}\) | |
| \(\frac{2}{5}\)y - \(\frac{2}{5}\) | |
| -\(\frac{5}{8}\)y - \(\frac{1}{8}\) |