ASVAB Math Knowledge Practice Test 204825

Question 1 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 6c + 3c = 5c - 9y - 9 for c in terms of y.

\(\frac{10}{13}\)y + \(\frac{4}{13}\)
-2\(\frac{1}{2}\)y + 4\(\frac{1}{2}\)
-12y - 9
\(\frac{3}{10}\)y - \(\frac{9}{10}\)