When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -6c - 5c = -9c + 3z + 6 for c in terms of z.
| 2\(\frac{2}{3}\)z + 2 | |
| -\(\frac{1}{9}\)z + \(\frac{8}{9}\) | |
| -12z - 9 | |
| -1\(\frac{5}{6}\)z - \(\frac{1}{2}\) |