When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 3c + 2c = -8c + 2z - 1 for c in terms of z.
| 5\(\frac{1}{2}\)z + \(\frac{1}{2}\) | |
| z - \(\frac{1}{11}\) | |
| \(\frac{1}{4}\)z - \(\frac{3}{4}\) | |
| \(\frac{9}{11}\)z - \(\frac{7}{11}\) |