When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 6c + 3c = -3c + 8x + 9 for c in terms of x.
| 4\(\frac{1}{3}\)x + 2\(\frac{1}{3}\) | |
| \(\frac{5}{9}\)x + 1 | |
| x - \(\frac{1}{17}\) | |
| -1\(\frac{2}{9}\)x + \(\frac{2}{9}\) |