When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 4c + 2c = 3c + 6x - 1 for c in terms of x.
| 4x - 1 | |
| 8\(\frac{1}{2}\)x - 2\(\frac{1}{2}\) | |
| -x - \(\frac{1}{6}\) | |
| 1\(\frac{3}{11}\)x + \(\frac{3}{11}\) |