ASVAB Math Knowledge Practice Test 211733

Question 4 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 7c - 4c = 6c + 3z - 3 for c in terms of z.

\(\frac{5}{6}\)z + \(\frac{2}{3}\)
-\(\frac{13}{17}\)z - \(\frac{2}{17}\)
\(\frac{1}{2}\)z - \(\frac{1}{3}\)
7z - 3