| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.77 |
| Score | 0% | 55% |
If BD = 22 and AD = 24, AB = ?
| 5 | |
| 12 | |
| 9 | |
| 2 |
The entire length of this line is represented by AD which is AB + BD:
AD = AB + BD
Solving for AB:AB = AD - BDWhich types of triangles will always have at least two sides of equal length?
equilateral, isosceles and right |
|
equilateral and isosceles |
|
equilateral and right |
|
isosceles and right |
An isosceles triangle has two sides of equal length. An equilateral triangle has three sides of equal length. In a right triangle, two sides meet at a right angle.
If side a = 5, side b = 7, what is the length of the hypotenuse of this right triangle?
| \( \sqrt{73} \) | |
| \( \sqrt{74} \) | |
| \( \sqrt{128} \) | |
| \( \sqrt{117} \) |
According to the Pythagorean theorem, the hypotenuse squared is equal to the sum of the two perpendicular sides squared:
c2 = a2 + b2
c2 = 52 + 72
c2 = 25 + 49
c2 = 74
c = \( \sqrt{74} \)
The dimensions of this cylinder are height (h) = 1 and radius (r) = 1. What is the surface area?
| 182π | |
| 40π | |
| 156π | |
| 4π |
The surface area of a cylinder is 2πr2 + 2πrh:
sa = 2πr2 + 2πrh
sa = 2π(12) + 2π(1 x 1)
sa = 2π(1) + 2π(1)
sa = (2 x 1)π + (2 x 1)π
sa = 2π + 2π
sa = 4π
Solve 2b - 2b = 9b - 2z - 6 for b in terms of z.
| 4z - 8 | |
| z + \(\frac{6}{7}\) | |
| -1\(\frac{1}{5}\)z - \(\frac{4}{5}\) | |
| -2\(\frac{3}{4}\)z - \(\frac{3}{4}\) |
To solve this equation, isolate the variable for which you are solving (b) on one side of the equation and put everything else on the other side.
2b - 2z = 9b - 2z - 6
2b = 9b - 2z - 6 + 2z
2b - 9b = -2z - 6 + 2z
-7b = - 6
b = \( \frac{ - 6}{-7} \)
b = \( \frac{}{-7} \) + \( \frac{-6}{-7} \)
b = z + \(\frac{6}{7}\)