When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 4c - 3c = 8c + 9z + 4 for c in terms of z.
| 2\(\frac{2}{5}\)z - 1\(\frac{4}{5}\) | |
| z - 2 | |
| -3z - 1 | |
| 5z + 8 |