When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -9b - 2b = 9b - 6z + 1 for b in terms of z.
| \(\frac{2}{9}\)z - \(\frac{1}{18}\) | |
| 2\(\frac{5}{6}\)z - \(\frac{1}{2}\) | |
| \(\frac{1}{3}\)z - \(\frac{5}{12}\) | |
| 1\(\frac{1}{3}\)z + 1\(\frac{1}{3}\) |