When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 3c - 2c = -3c - 6x - 5 for c in terms of x.
| -2\(\frac{2}{5}\)x + 1\(\frac{4}{5}\) | |
| 1\(\frac{1}{4}\)x - \(\frac{1}{12}\) | |
| -\(\frac{2}{3}\)x - \(\frac{5}{6}\) | |
| 14x + 4 |