| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.53 |
| Score | 0% | 51% |
Which of the following statements about parallel lines with a transversal is not correct?
all of the angles formed by a transversal are called interior angles |
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angles in the same position on different parallel lines are called corresponding angles |
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same-side interior angles are complementary and equal each other |
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all acute angles equal each other |
Parallel lines are lines that share the same slope (steepness) and therefore never intersect. A transversal occurs when a set of parallel lines are crossed by another line. All of the angles formed by a transversal are called interior angles and angles in the same position on different parallel lines equal each other (a° = w°, b° = x°, c° = z°, d° = y°) and are called corresponding angles. Alternate interior angles are equal (a° = z°, b° = y°, c° = w°, d° = x°) and all acute angles (a° = c° = w° = z°) and all obtuse angles (b° = d° = x° = y°) equal each other. Same-side interior angles are supplementary and add up to 180° (e.g. a° + d° = 180°, d° + c° = 180°).
If side a = 7, side b = 1, what is the length of the hypotenuse of this right triangle?
| \( \sqrt{50} \) | |
| \( \sqrt{61} \) | |
| \( \sqrt{29} \) | |
| \( \sqrt{85} \) |
According to the Pythagorean theorem, the hypotenuse squared is equal to the sum of the two perpendicular sides squared:
c2 = a2 + b2
c2 = 72 + 12
c2 = 49 + 1
c2 = 50
c = \( \sqrt{50} \)
When two lines intersect, adjacent angles are __________ (they add up to 180°) and angles across from either other are __________ (they're equal).
acute, obtuse |
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vertical, supplementary |
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obtuse, acute |
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supplementary, vertical |
Angles around a line add up to 180°. Angles around a point add up to 360°. When two lines intersect, adjacent angles are supplementary (they add up to 180°) and angles across from either other are vertical (they're equal).
The dimensions of this trapezoid are a = 4, b = 9, c = 5, d = 3, and h = 3. What is the area?
| 18 | |
| 10 | |
| 24 | |
| 22\(\frac{1}{2}\) |
The area of a trapezoid is one-half the sum of the lengths of the parallel sides multiplied by the height:
a = ½(b + d)(h)
a = ½(9 + 3)(3)
a = ½(12)(3)
a = ½(36) = \( \frac{36}{2} \)
a = 18
Solve for c:
-4c - 1 < \( \frac{c}{3} \)
| c < -\(\frac{3}{13}\) | |
| c < \(\frac{8}{63}\) | |
| c < -\(\frac{27}{28}\) | |
| c < -3\(\frac{1}{3}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the < sign and the answer on the other.
-4c - 1 < \( \frac{c}{3} \)
3 x (-4c - 1) < c
(3 x -4c) + (3 x -1) < c
-12c - 3 < c
-12c - 3 - c < 0
-12c - c < 3
-13c < 3
c < \( \frac{3}{-13} \)
c < -\(\frac{3}{13}\)