When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 2c + 3c = -2c + 3z + 3 for c in terms of z.
| 7\(\frac{1}{2}\)z + 3\(\frac{1}{2}\) | |
| -\(\frac{1}{5}\)z + 1\(\frac{2}{5}\) | |
| 3\(\frac{1}{2}\)z + 4\(\frac{1}{2}\) | |
| z + \(\frac{3}{4}\) |