| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.74 |
| Score | 0% | 55% |
On this circle, line segment CD is the:
radius |
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diameter |
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circumference |
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chord |
A circle is a figure in which each point around its perimeter is an equal distance from the center. The radius of a circle is the distance between the center and any point along its perimeter. A chord is a line segment that connects any two points along its perimeter. The diameter of a circle is the length of a chord that passes through the center of the circle and equals twice the circle's radius (2r).
Which of the following statements about a parallelogram is not true?
opposite sides and adjacent angles are equal |
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a parallelogram is a quadrilateral |
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the area of a parallelogram is base x height |
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the perimeter of a parallelogram is the sum of the lengths of all sides |
A parallelogram is a quadrilateral with two sets of parallel sides. Opposite sides (a = c, b = d) and angles (red = red, blue = blue) are equal. The area of a parallelogram is base x height and the perimeter is the sum of the lengths of all sides (a + b + c + d).
Solve for c:
c2 - 13c + 36 = 0
| 9 or 6 | |
| 1 or -2 | |
| 4 or 9 | |
| -2 or -7 |
The first step to solve a quadratic equation that's set to zero is to factor the quadratic equation:
c2 - 13c + 36 = 0
(c - 4)(c - 9) = 0
For this expression to be true, the left side of the expression must equal zero. Therefore, either (c - 4) or (c - 9) must equal zero:
If (c - 4) = 0, c must equal 4
If (c - 9) = 0, c must equal 9
So the solution is that c = 4 or 9
Breaking apart a quadratic expression into a pair of binomials is called:
normalizing |
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squaring |
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factoring |
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deconstructing |
To factor a quadratic expression, apply the FOIL (First, Outside, Inside, Last) method in reverse.
Solve for y:
5y + 2 > \( \frac{y}{8} \)
| y > \(\frac{5}{46}\) | |
| y > -\(\frac{16}{39}\) | |
| y > -\(\frac{21}{34}\) | |
| y > \(\frac{27}{62}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the > sign and the answer on the other.
5y + 2 > \( \frac{y}{8} \)
8 x (5y + 2) > y
(8 x 5y) + (8 x 2) > y
40y + 16 > y
40y + 16 - y > 0
40y - y > -16
39y > -16
y > \( \frac{-16}{39} \)
y > -\(\frac{16}{39}\)