ASVAB Math Knowledge Practice Test 219864 Results

Your Results Global Average
Questions 5 5
Correct 0 2.74
Score 0% 55%

Review

1

On this circle, line segment CD is the:

46% Answer Correctly

radius

diameter

circumference

chord


Solution

A circle is a figure in which each point around its perimeter is an equal distance from the center. The radius of a circle is the distance between the center and any point along its perimeter. A chord is a line segment that connects any two points along its perimeter. The diameter of a circle is the length of a chord that passes through the center of the circle and equals twice the circle's radius (2r).


2

Which of the following statements about a parallelogram is not true?

50% Answer Correctly

opposite sides and adjacent angles are equal

a parallelogram is a quadrilateral

the area of a parallelogram is base x height

the perimeter of a parallelogram is the sum of the lengths of all sides


Solution

A parallelogram is a quadrilateral with two sets of parallel sides. Opposite sides (a = c, b = d) and angles (red = red, blue = blue) are equal. The area of a parallelogram is base x height and the perimeter is the sum of the lengths of all sides (a + b + c + d).


3

Solve for c:
c2 - 13c + 36 = 0

58% Answer Correctly
9 or 6
1 or -2
4 or 9
-2 or -7

Solution

The first step to solve a quadratic equation that's set to zero is to factor the quadratic equation:

c2 - 13c + 36 = 0
(c - 4)(c - 9) = 0

For this expression to be true, the left side of the expression must equal zero. Therefore, either (c - 4) or (c - 9) must equal zero:

If (c - 4) = 0, c must equal 4
If (c - 9) = 0, c must equal 9

So the solution is that c = 4 or 9


4

Breaking apart a quadratic expression into a pair of binomials is called:

74% Answer Correctly

normalizing

squaring

factoring

deconstructing


Solution

To factor a quadratic expression, apply the FOIL (First, Outside, Inside, Last) method in reverse.


5

Solve for y:
5y + 2 > \( \frac{y}{8} \)

44% Answer Correctly
y > \(\frac{5}{46}\)
y > -\(\frac{16}{39}\)
y > -\(\frac{21}{34}\)
y > \(\frac{27}{62}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the > sign and the answer on the other.

5y + 2 > \( \frac{y}{8} \)
8 x (5y + 2) > y
(8 x 5y) + (8 x 2) > y
40y + 16 > y
40y + 16 - y > 0
40y - y > -16
39y > -16
y > \( \frac{-16}{39} \)
y > -\(\frac{16}{39}\)