ASVAB Math Knowledge Practice Test 220028

Question 4 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 9c - 3c = 8c + 8y - 9 for c in terms of y.

\(\frac{1}{4}\)y + \(\frac{5}{8}\)
\(\frac{2}{3}\)y - \(\frac{1}{3}\)
11y - 9
-\(\frac{2}{5}\)y + \(\frac{2}{5}\)