When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -4c + c = 6c - 8z - 8 for c in terms of z.
| \(\frac{9}{10}\)z + \(\frac{4}{5}\) | |
| -4z - 1 | |
| 1\(\frac{2}{9}\)z + \(\frac{8}{9}\) | |
| \(\frac{2}{5}\)z - 1\(\frac{1}{5}\) |