When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 6c - 5c = -7c + y + 3 for c in terms of y.
| 1\(\frac{3}{4}\)y + \(\frac{7}{8}\) | |
| \(\frac{6}{13}\)y + \(\frac{3}{13}\) | |
| -\(\frac{1}{4}\)y + \(\frac{3}{8}\) | |
| -\(\frac{3}{10}\)y - \(\frac{4}{5}\) |