ASVAB Math Knowledge Practice Test 221584

Question 4 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 4a - 4a = 3a + 5z - 6 for a in terms of z.

-1\(\frac{1}{6}\)z - \(\frac{1}{6}\)
\(\frac{1}{4}\)z - 1
9z - 6
1\(\frac{1}{8}\)z - \(\frac{3}{8}\)