ASVAB Math Knowledge Practice Test 222835 Results

Your Results Global Average
Questions 5 5
Correct 0 3.00
Score 0% 60%

Review

1

The dimensions of this cylinder are height (h) = 1 and radius (r) = 4. What is the surface area?

48% Answer Correctly
176π
18π
48π
40π

Solution

The surface area of a cylinder is 2πr2 + 2πrh:

sa = 2πr2 + 2πrh
sa = 2π(42) + 2π(4 x 1)
sa = 2π(16) + 2π(4)
sa = (2 x 16)π + (2 x 4)π
sa = 32π + 8π
sa = 40π


2

To multiply binomials, use the FOIL method. Which of the following is not a part of the FOIL method?

84% Answer Correctly

Inside

First

Last

Odd


Solution

To multiply binomials, use the FOIL method. FOIL stands for First, Outside, Inside, Last and refers to the position of each term in the parentheses.


3

Which of the following statements about math operations is incorrect?

71% Answer Correctly

you can add monomials that have the same variable and the same exponent

you can multiply monomials that have different variables and different exponents

all of these statements are correct

you can subtract monomials that have the same variable and the same exponent


Solution

You can only add or subtract monomials that have the same variable and the same exponent. For example, 2a + 4a = 6a and 4a2 - a2 = 3a2 but 2a + 4b and 7a - 3b cannot be combined. However, you can multiply and divide monomials with unlike terms. For example, 2a x 6b = 12ab.


4

Solve for b:
3b + 2 = 3 + b

59% Answer Correctly
-1\(\frac{1}{2}\)
-1\(\frac{1}{4}\)
\(\frac{1}{2}\)
-\(\frac{2}{3}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.

3b + 2 = 3 + b
3b = 3 + b - 2
3b - b = 3 - 2
2b = 1
b = \( \frac{1}{2} \)
b = \(\frac{1}{2}\)


5

Solve 5a + 3a = 2a + 9y - 3 for a in terms of y.

34% Answer Correctly
2y - 1
-2y + 1\(\frac{1}{4}\)
-\(\frac{3}{4}\)y - \(\frac{3}{4}\)
-1\(\frac{1}{6}\)y + \(\frac{1}{6}\)

Solution

To solve this equation, isolate the variable for which you are solving (a) on one side of the equation and put everything else on the other side.

5a + 3y = 2a + 9y - 3
5a = 2a + 9y - 3 - 3y
5a - 2a = 9y - 3 - 3y
3a = 6y - 3
a = \( \frac{6y - 3}{3} \)
a = \( \frac{6y}{3} \) + \( \frac{-3}{3} \)
a = 2y - 1