| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.72 |
| Score | 0% | 54% |
Which of the following statements about a triangle is not true?
sum of interior angles = 180° |
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perimeter = sum of side lengths |
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exterior angle = sum of two adjacent interior angles |
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area = ½bh |
A triangle is a three-sided polygon. It has three interior angles that add up to 180° (a + b + c = 180°). An exterior angle of a triangle is equal to the sum of the two interior angles that are opposite (d = b + c). The perimeter of a triangle is equal to the sum of the lengths of its three sides, the height of a triangle is equal to the length from the base to the opposite vertex (angle) and the area equals one-half triangle base x height: a = ½ base x height.
On this circle, line segment CD is the:
diameter |
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circumference |
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radius |
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chord |
A circle is a figure in which each point around its perimeter is an equal distance from the center. The radius of a circle is the distance between the center and any point along its perimeter. A chord is a line segment that connects any two points along its perimeter. The diameter of a circle is the length of a chord that passes through the center of the circle and equals twice the circle's radius (2r).
If angle a = 58° and angle b = 41° what is the length of angle d?
| 132° | |
| 130° | |
| 122° | |
| 120° |
An exterior angle of a triangle is equal to the sum of the two interior angles that are opposite:
d° = b° + c°
To find angle c, remember that the sum of the interior angles of a triangle is 180°:
180° = a° + b° + c°
c° = 180° - a° - b°
c° = 180° - 58° - 41° = 81°
So, d° = 41° + 81° = 122°
A shortcut to get this answer is to remember that angles around a line add up to 180°:
a° + d° = 180°
d° = 180° - a°
d° = 180° - 58° = 122°
Solve for y:
6y + 3 < -8 - 6y
| y < -1 | |
| y < -\(\frac{3}{5}\) | |
| y < -5 | |
| y < -\(\frac{11}{12}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the < sign and the answer on the other.
6y + 3 < -8 - 6y
6y < -8 - 6y - 3
6y + 6y < -8 - 3
12y < -11
y < \( \frac{-11}{12} \)
y < -\(\frac{11}{12}\)
Solve for c:
c2 - 11c + 24 = 0
| 7 or -8 | |
| 7 or -9 | |
| 3 or 8 | |
| 4 or 1 |
The first step to solve a quadratic equation that's set to zero is to factor the quadratic equation:
c2 - 11c + 24 = 0
(c - 3)(c - 8) = 0
For this expression to be true, the left side of the expression must equal zero. Therefore, either (c - 3) or (c - 8) must equal zero:
If (c - 3) = 0, c must equal 3
If (c - 8) = 0, c must equal 8
So the solution is that c = 3 or 8