ASVAB Math Knowledge Practice Test 2234 Results

Your Results Global Average
Questions 5 5
Correct 0 3.26
Score 0% 65%

Review

1

Which of the following statements about math operations is incorrect?

71% Answer Correctly

all of these statements are correct

you can multiply monomials that have different variables and different exponents

you can subtract monomials that have the same variable and the same exponent

you can add monomials that have the same variable and the same exponent


Solution

You can only add or subtract monomials that have the same variable and the same exponent. For example, 2a + 4a = 6a and 4a2 - a2 = 3a2 but 2a + 4b and 7a - 3b cannot be combined. However, you can multiply and divide monomials with unlike terms. For example, 2a x 6b = 12ab.


2

Solve 2b + 5b = 6b + 4x + 7 for b in terms of x.

34% Answer Correctly
-6\(\frac{1}{2}\)x + 1
6x + 7
1\(\frac{1}{5}\)x + \(\frac{1}{5}\)
\(\frac{1}{4}\)x - 1\(\frac{3}{4}\)

Solution

To solve this equation, isolate the variable for which you are solving (b) on one side of the equation and put everything else on the other side.

2b + 5x = 6b + 4x + 7
2b = 6b + 4x + 7 - 5x
2b - 6b = 4x + 7 - 5x
-4b = -x + 7
b = \( \frac{-x + 7}{-4} \)
b = \( \frac{-x}{-4} \) + \( \frac{7}{-4} \)
b = \(\frac{1}{4}\)x - 1\(\frac{3}{4}\)


3

If the area of this square is 9, what is the length of one of the diagonals?

68% Answer Correctly
3\( \sqrt{2} \)
7\( \sqrt{2} \)
2\( \sqrt{2} \)
4\( \sqrt{2} \)

Solution

To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:

a = s2

so the length of one side of the square is:

s = \( \sqrt{a} \) = \( \sqrt{9} \) = 3

The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:

c2 = a2 + b2
c2 = 32 + 32
c2 = 18
c = \( \sqrt{18} \) = \( \sqrt{9 x 2} \) = \( \sqrt{9} \) \( \sqrt{2} \)
c = 3\( \sqrt{2} \)


4

If BD = 10 and AD = 20, AB = ?

76% Answer Correctly
2
7
16
10

Solution

The entire length of this line is represented by AD which is AB + BD:

AD = AB + BD

Solving for AB:

AB = AD - BD
AB = 20 - 10
AB = 10


5

Breaking apart a quadratic expression into a pair of binomials is called:

75% Answer Correctly

normalizing

squaring

deconstructing

factoring


Solution

To factor a quadratic expression, apply the FOIL (First, Outside, Inside, Last) method in reverse.