When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 4c + c = 3c - 2x - 5 for c in terms of x.
| \(\frac{2}{5}\)x + 1\(\frac{1}{5}\) | |
| -3x - 3 | |
| 2x - \(\frac{5}{6}\) | |
| -3x - 5 |