ASVAB Math Knowledge Practice Test 226144 Results

Your Results Global Average
Questions 5 5
Correct 0 2.61
Score 0% 52%

Review

1

A cylinder with a radius (r) and a height (h) has a surface area of:

54% Answer Correctly

4π r2

π r2h

2(π r2) + 2π rh

π r2h2


Solution

A cylinder is a solid figure with straight parallel sides and a circular or oval cross section with a radius (r) and a height (h). The volume of a cylinder is π r2h and the surface area is 2(π r2) + 2π rh.


2

This diagram represents two parallel lines with a transversal. If b° = 149, what is the value of a°?

73% Answer Correctly
155
148
143
31

Solution

For parallel lines with a transversal, the following relationships apply:

  • angles in the same position on different parallel lines equal each other (a° = w°, b° = x°, c° = z°, d° = y°)
  • alternate interior angles are equal (a° = z°, b° = y°, c° = w°, d° = x°)
  • all acute angles (a° = c° = w° = z°) and all obtuse angles (b° = d° = x° = y°) equal each other
  • same-side interior angles are supplementary and add up to 180° (e.g. a° + d° = 180°, d° + c° = 180°)

Applying these relationships starting with b° = 149, the value of a° is 31.


3

The dimensions of this cylinder are height (h) = 4 and radius (r) = 2. What is the surface area?

48% Answer Correctly
72π
12π
28π
24π

Solution

The surface area of a cylinder is 2πr2 + 2πrh:

sa = 2πr2 + 2πrh
sa = 2π(22) + 2π(2 x 4)
sa = 2π(4) + 2π(8)
sa = (2 x 4)π + (2 x 8)π
sa = 8π + 16π
sa = 24π


4

The dimensions of this cube are height (h) = 4, length (l) = 8, and width (w) = 7. What is the surface area?

51% Answer Correctly
232
30
202
228

Solution

The surface area of a cube is (2 x length x width) + (2 x width x height) + (2 x length x height):

sa = 2lw + 2wh + 2lh
sa = (2 x 8 x 7) + (2 x 7 x 4) + (2 x 8 x 4)
sa = (112) + (56) + (64)
sa = 232


5

Solve 2b + 5b = -b - 9z + 2 for b in terms of z.

34% Answer Correctly
-\(\frac{1}{4}\)z + \(\frac{7}{8}\)
-4\(\frac{2}{3}\)z + \(\frac{2}{3}\)
3\(\frac{1}{4}\)z + 2
z + \(\frac{3}{8}\)

Solution

To solve this equation, isolate the variable for which you are solving (b) on one side of the equation and put everything else on the other side.

2b + 5z = -b - 9z + 2
2b = -b - 9z + 2 - 5z
2b + b = -9z + 2 - 5z
3b = -14z + 2
b = \( \frac{-14z + 2}{3} \)
b = \( \frac{-14z}{3} \) + \( \frac{2}{3} \)
b = -4\(\frac{2}{3}\)z + \(\frac{2}{3}\)