When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -4c + 6c = 2c + 5y - 5 for c in terms of y.
| -\(\frac{2}{5}\)y - 1 | |
| 2y + \(\frac{1}{3}\) | |
| \(\frac{1}{6}\)y + \(\frac{5}{6}\) | |
| \(\frac{4}{15}\)y + \(\frac{2}{15}\) |