When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 8c + 3c = 6c - 2y + 3 for c in terms of y.
| -2\(\frac{1}{2}\)y + 1\(\frac{1}{2}\) | |
| 17y - 5 | |
| -\(\frac{2}{9}\)y - \(\frac{1}{9}\) | |
| 6y - 8 |