When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 8c + 9c = 3c - 3y - 5 for c in terms of y.
| -1\(\frac{2}{9}\)y - 1 | |
| \(\frac{1}{4}\)y + 2\(\frac{1}{4}\) | |
| \(\frac{1}{6}\)y + 1\(\frac{1}{3}\) | |
| -2\(\frac{2}{5}\)y - 1 |