When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -c + 8c = 2c + 2z + 4 for c in terms of z.
| \(\frac{3}{4}\)z + \(\frac{1}{2}\) | |
| -1\(\frac{1}{6}\)z - \(\frac{1}{6}\) | |
| 2z - 1\(\frac{1}{3}\) | |
| -\(\frac{1}{10}\)z + \(\frac{4}{5}\) |