When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -3c - 8c = -4c + z - 1 for c in terms of z.
| z + \(\frac{1}{3}\) | |
| \(\frac{1}{2}\)z + \(\frac{1}{4}\) | |
| -6z + 1 | |
| 9z - 1 |