| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.21 |
| Score | 0% | 64% |
The endpoints of this line segment are at (-2, -3) and (2, 7). What is the slope-intercept equation for this line?
| y = 2\(\frac{1}{2}\)x + 2 | |
| y = 3x + 1 | |
| y = \(\frac{1}{2}\)x + 2 | |
| y = -2x - 1 |
The slope-intercept equation for a line is y = mx + b where m is the slope and b is the y-intercept of the line. From the graph, you can see that the y-intercept (the y-value from the point where the line crosses the y-axis) is 2. The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, -3) and (2, 7) so the slope becomes:
m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(7.0) - (-3.0)}{(2) - (-2)} \) = \( \frac{10}{4} \)Plugging these values into the slope-intercept equation:
y = 2\(\frac{1}{2}\)x + 2
Simplify 7a x 4b.
| 28ab | |
| 28a2b2 | |
| 11ab | |
| 28\( \frac{a}{b} \) |
To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.
7a x 4b = (7 x 4) (a x b) = 28ab
Which types of triangles will always have at least two sides of equal length?
isosceles and right |
|
equilateral and isosceles |
|
equilateral and right |
|
equilateral, isosceles and right |
An isosceles triangle has two sides of equal length. An equilateral triangle has three sides of equal length. In a right triangle, two sides meet at a right angle.
Simplify (5a)(7ab) - (7a2)(7b).
| -14a2b | |
| 168ab2 | |
| 168a2b | |
| 84ab2 |
To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.
(5a)(7ab) - (7a2)(7b)
(5 x 7)(a x a x b) - (7 x 7)(a2 x b)
(35)(a1+1 x b) - (49)(a2b)
35a2b - 49a2b
-14a2b
If AD = 14 and BD = 6, AB = ?
| 14 | |
| 9 | |
| 8 | |
| 10 |
The entire length of this line is represented by AD which is AB + BD:
AD = AB + BD
Solving for AB:AB = AD - BD