When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 4c + 5c = -8c + 5y - 4 for c in terms of y.
| \(\frac{9}{11}\)y + \(\frac{4}{11}\) | |
| 2\(\frac{1}{6}\)y + 1\(\frac{1}{3}\) | |
| y - \(\frac{1}{3}\) | |
| 1\(\frac{4}{5}\)y + \(\frac{3}{5}\) |