When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 8c - 3c = -9c - 6z + 1 for c in terms of z.
| -1\(\frac{1}{10}\)z - \(\frac{3}{5}\) | |
| -\(\frac{6}{7}\)z + \(\frac{3}{7}\) | |
| -13z + 5 | |
| -\(\frac{3}{17}\)z + \(\frac{1}{17}\) |