When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 3c - c = -2c - 2z + 4 for c in terms of z.
| 4\(\frac{2}{3}\)z - 1\(\frac{2}{3}\) | |
| -1\(\frac{2}{3}\)z - 1\(\frac{1}{6}\) | |
| -\(\frac{1}{5}\)z + \(\frac{4}{5}\) | |
| -1\(\frac{8}{9}\)z - 1 |