When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 8c - 2c = 5c + 4z - 2 for c in terms of z.
| \(\frac{3}{8}\)z - 1\(\frac{1}{8}\) | |
| 2\(\frac{1}{3}\)z - 1\(\frac{1}{3}\) | |
| -\(\frac{9}{10}\)z + \(\frac{3}{10}\) | |
| 2z - \(\frac{2}{3}\) |