When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 4c - 3c = -6c + 2z - 2 for c in terms of z.
| \(\frac{3}{4}\)z + \(\frac{7}{12}\) | |
| \(\frac{1}{2}\)z - \(\frac{1}{5}\) | |
| 10z - 8 | |
| -1\(\frac{2}{5}\)z - 1\(\frac{3}{5}\) |