ASVAB Math Knowledge Practice Test 24018

Question 1 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve -3c + 4c = 7c - 3y + 2 for c in terms of y.

1\(\frac{3}{4}\)y - 2\(\frac{1}{4}\)
-2\(\frac{2}{3}\)y - 1\(\frac{1}{3}\)
1\(\frac{1}{6}\)y + \(\frac{1}{2}\)
\(\frac{7}{10}\)y - \(\frac{1}{5}\)